: u Calculate e

---

Result	TIME Limit	MEMORY Limit	Run Times	AC Times	JUDGE
	3s	8192K	6098	1521	Standard

Background

A simple mathematical formula for e is

 

where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

 

Sample Output

 

n e- -----------0 11 22 2.53 2.6666666674 2.708333333

#include
     
       double factoral(double); double showsum(int ); int main(void) {
   int n, i; double sum = 0;     printf("n e\n");     printf("- -----------\n");     printf("0 1\n");     printf("1 2\n");     printf("2 2.5\n"); for (i=3; i<=9; i++)     {
           printf("%d ", i);         printf("%.9lf\n",1+showsum(i));     } return 0; } double factoral(double i) {
   if (i == 0) return 1; else return i*factoral(i-1); } double showsum(int n) {    double sum=0; for(int i=1;i<=n;i++)     {
           sum+=(double)1/factoral(i);     } return sum; }
     

 

---

This problem is used for contest:

---

/ / /